Question: A multiple-drilling machine is used to drill simultaneously six holes in the steel plate shown. Each drill exerts a clockwise couple of magnitude 40 lb? in. on the plate. Determine an equivalent couple formed by the smallest possible forces acting (a) at A and C, (b) at A and D, (c) on the plate.
Answer:
a)
Mc = 40 lb-in * 6 holes = 240 lb-in Mc = F*d
240 lb-in = F*12 in
F = 20 lb ---> answer
b)
AD = SQRT(12^2 + 9^2) = 15 in Mc = F*d
240 = F*15
F = 16 lb ----> answer
c)
BC = SQRT(12^2 + 16^2) = 20 in Mc = F*d
240 = F*20
F = 12 lb ---> answer

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